(2x^2+1)/(x^2-1)

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Solution for (2x^2+1)/(x^2-1) equation: 


D( x )

x^2-1 = 0

x^2-1 = 0

x^2-1 = 0

1*x^2 = 1 // : 1

x^2 = 1

x^2 = 1 // ^ 1/2

abs(x) = 1

x = 1 or x = -1

x in (-oo:-1) U (-1:1) U (1:+oo)

(2*x^2+1)/(x^2-1) = 0

2*x^2 = -1 // : 2

x^2 = -1/2

x belongs to the empty set

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